3n^2+9n-7=0

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Solution for 3n^2+9n-7=0 equation: 



3n^2+9n-7=0

a = 3; b = 9; c = -7;
Δ = b2-4ac
Δ = 92-4·3·(-7)
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{165}}{2*3}=\frac{-9-\sqrt{165}}{6}
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{165}}{2*3}=\frac{-9+\sqrt{165}}{6}
$

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